9514 1404 393
Answer:
3
Step-by-step explanation:
Let x represent the number. The problem statement tells you ...
2/3(3x +6) = 10
2x +4 = 10 . . . . . . use the distributive property
x +2 = 5 . . . . . . . . divide by 2
x = 3 . . . . . . . . . . .subtract 3
The number is 3.
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<em>Comment on the solution</em>
The above shows an "alternative" solution method. The more usual way this might be done is ...
2(3x +6) = 30 . . . . . multiply by 3 to clear fractions
6x +12 = 30 . . . . . . . eliminate parentheses
6x = 18 . . . . . . . . . . . subtract 12
x = 3 . . . . . . . . . . . . divide by 6
So, since the polygons are similar, they will share a scale factor.
The dilation is a reduction.
SF= preimage/image
SF=48/40
SF= 1.2
To find the value of x, multiply 20 by 1.2, so:
20(1.2)=24
Thus, x = 24
Now, to check if the sides are proportional (this will determine if the polygons are, in fact, similar.)
24/20=1.2
48/40=1.2
BTW, the missing side measure for the image is 40 since 48 is its corresponding side, and 48/1.2 (SF) is 40.
Hence, we have 48/40= 1.2
<span>ʕ •ᴥ•ʔ</span>
Answer:
Zeke ran 9 laps.
Step-by-step explanation:
Answer:
x = 9.1
Step-by-step explanation:
x^2 + 16^2 = 18.4^2
x^2 + 256 = 338.56
x^2 = 82.56
x = 9.1
The options of the question are
A.)BFC B.)CFG C.)GFD D.)EFA
we know that
A linear pair forms a straight angle which contains 
º, so you have 
angles whose measures add to degrees, which means they are supplementary.
Vertical Angles are two angles whose sides form two pairs of opposite rays (straight lines).Vertical angles are congruent
in this problem
Part a) Linear Pair
1) m∠EFA+m∠EFD=°
angles ∠EFA and ∠EFD are a linear pair
2) m∠BFD+m∠EFD=°
angles ∠BFD and ∠EFD are a linear pair
3) m∠BFD+m∠BFA=°
angles ∠BFD and ∠BFA are a linear pair
4) m∠BFA+m∠AFD=°
angles ∠BFA and ∠AFD are a linear pair
Part b) Vertical angles
1) m∠EFA=m∠BFD
angles ∠EFA and ∠BFD are a vertical angles
2) m∠AFB=m∠EFD
angles ∠AFB and ∠EFD are a vertical angles
therefore
the answer is the option
D.) EFA
