Find the area of a square whose side is 9.4cm .
1 answer:
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Answer:A
Step-by-step explanation:
Given
Turning Point is the point where the graph changes its nature i.e. either increasing to decreasing or decreasing to increasing
to find turning point
For critical point
F'(x)=0
x+2=0
x=-2
thus
(-2,-4 ) is the turning Point where Function changes its nature
The answer is 114sqrt{6} in³
A regular hexahedron is actually a cube.
Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²
Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²
D² = f² + a²
f² = 2a²
D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3
Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3
V = a³ = (D/√3)³
We have:
D = 8√2 in
A regular hexahedron is actually a cube.
Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²
Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²
D² = f² + a²
f² = 2a²
D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3
Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3
V = a³ = (D/√3)³
We have:
D = 8√2 in