Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Answer:
yes she can
Step-by-step explanation:
430,825 because if you add them up you get this
4.2^n+12^n+2/2^n+12^n
Step-by-step explanation:
I'd say Yana has 6...
30\ 6 is 5
the ratio range is a group inside 5..
so Dina has 30 swim suits...which is 5 times 6 of yana.
so since Dina has 24 "more" than yana... Dina is 4 : Yana is 1....4:1
