I need help please.
2 answers:
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Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiply both sides by 100.
Divide both sides by 50.
The amount invested at 7% is .
The amount invested at 8% is
The amount invested at 9% is
Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
(6,2)
Step by Step explanation:
1- Add the two equations so the Xs cancel out
2- find y by dividing 6 from both sides
3- plug in the y value in the place of the y in one of the equations
4- solve the equation to find X
5 - put answer in correct format (x,y)
