Answer:
No solution
Step-by-step explanation:
Muah ha ha ha ha ha ha
Answer:
- f = -2/5a +14
- 12.4 ≈ 12 fish for 4 algae blooms
Step-by-step explanation:
The 2-point form of the equation for a line is useful when you are given two points to work with:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
The independent variable (x) is apparently "algae blooms" and is to be represented by "a". The dependent variable (y) is "number of fish" and is to be represented by "f". So, we have ...
f = (4 -10)/(25 -10)(a -10) +10
f = -6/15(a -10) +10
f = -2/5a +14 . . . an equation for the scenario
Four a=4, the fish population is predicted to be ...
f = -2/5(4) +14 = 12.4
There will be about 12 fish when there are 4 algae blooms.
Answer:
1.97 years
Step-by-step explanation:
First, convert R as a percent to r as a decimal
r = R/100
r = 8/100
r = 0.08 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(17,500.00/15,000.00) / ( 2 × [ln(1 + 0.08/2)] )
t = ln(17,500.00/15,000.00) / ( 2 × [ln(1 + 0.04)] )
t = 1.965 years
:D
9 of his buttons are not red. 1/8 of 72 is 9
72×1/8=8
72÷8=9
Answer: X=5/2, Y= 15, T=4
