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3 years ago

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Please help me solve this with steps

1 answer:

OlgaM077 [116]3 years ago

6 0

Here is the answer for a:

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Reuben has scores of 70,75,83, and 80 on four spanish quizzes. what score must he get on the next quiz to achieve an average of

Sergio [31]

X - the score he must get

$\frac{70+75+83+80+x}{5} \geq 80 \\
\frac{308+x}{5} \geq 80 \\
308+x \geq 400 \\
x \geq 92$

He must get at least 92 points.

4 0

3 years ago

Read 2 more answers

There are 270 students at Colfax Middle School, where the ratio of boys to girls is 5:4. There are 180 students at Winthrop Midd

zavuch27 [327]

Given:

Total number of students at Colfax Middle School = 270

Ratio of boys to girls is 5:4.

Total number of students at Winthrop Middle School = 180

Ratio of boys to girls is 4:5.

The two schools hold a dance and all students from both schools attend.

To find:

The fraction of the students at the dance are girls

Solution:

There are 270 students at Colfax Middle School, where the ratio of boys to girls is 5:4.

$5+4=9$

Number of boys $=270\times \dfrac{5}{9}=150$

Number of girls $=270\times \dfrac{4}{9}=120$

There are 180 students at Winthrop Middle School, where the ratio of boys to girls is 4:5.

$4+5=9$

Number of boys $=180\times \dfrac{4}{9}=80$

Number of girls $=180\times \dfrac{5}{9}=100$

Now,

Total number of students in both schools $= 270+180$

$= 450$

Total number of girls in both schools $= 120+100$

$= 220$

The fraction of the students at the dance are girls is

$\text{Required fraction}=\dfrac{\text{Total number of girls in both schools}}{\text{Total number of students in both schools}}$

$\text{Required fraction}=\dfrac{220}{450}$

$\text{Required fraction}=\dfrac{22}{45}$

Therefore, the required fraction is $\dfrac{22}{45}$ .

7 0

3 years ago

Please answer if you can.

Mumz [18]

Answer:

25+24= 49coins 49÷2.5 is 19.5 so there are 19.5 dimes in the bag I believe

7 0

3 years ago

A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.

iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- $|E\ n\ B|$

- $|B|$

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

$B = \{6\}$

$E = \{2,4,6\}$

Calculating the size of |E n B|

$|E n B| = \{2,4,6\}\ n\ \{6\}$

$|E n B| = \{2,4,6\}$

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

$B = \{6\}$

<em>The size = 1 because it contains 1 possible outcome</em>

8 0

3 years ago

Question 5 of 24

Masja [62]

I think that the answer is c

7 0

3 years ago