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Nimfa-mama [501]
3 years ago
11

To evaluate the quality of the cellular phones coming off the assembly line, the manufacturer takes one every half-hour and test

s it. About 1 out of 10,000 is found to have a minor mechanical problem. The company assumes from this data that 1 out of every 10,000 cellular phones they produce will be returned for mechanical problems after being purchased. Determine whether this conclusion is valid. Justify your answer.
Mathematics
1 answer:
Xelga [282]3 years ago
6 0
Try to make sense out of this problem to where you can understand it
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Mixed number eqivalent to 51/5
mafiozo [28]
51/5 is equivalent to 10 and 1/5.

6 0
3 years ago
Find b. Question 19 options:<br><br><br>70.1<br><br><br>57.7<br><br><br>31.5<br><br><br>43.8
Reptile [31]

Answer: 57.7

Step-by-step explanation:

6 0
2 years ago
Determine the constant of proportionality.
Rudiy27

Answer:

2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Lalasa and yasmin are designing a triangular banner to hang in the school gymnasiums. They first draw the design on paper. The t
jasenka [17]
<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>

5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>

regarding feet: 

The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
</span>

3 0
2 years ago
Task: E = mc2
Afina-wow [57]

Answer:

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

Step-by-step explanation:

E = mc^2

$c^2=\frac{E}{m} $

$c=\sqrt{\frac{E}{m} } $

or

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

3 0
3 years ago
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