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Nutka1998 [239]
3 years ago
14

Use the given conditions to write an equation for each line in point-slope form and slope-intercept form.

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

(y - 0) =  \frac{1}{3} (x - 0)

y =  \frac{1}{3} x

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Kendrick’s bill for lunch was $24.50. He left the server an 18% tip. What is the total amount that Kendrick paid for lunch inclu
Mice21 [21]

Answer:

$28.91

Step-by-step explanation:

The first step is to calculate the amount of the tip. You multiply the price (24.50) by the tip amount (18% or 0.18). The product is 4.41. Then, you add the tip to the bill. 24.50+4.41=28.91.

7 0
3 years ago
Factor: 120u² + 125u + 30.
NemiM [27]

Answer:

5(3u+2)(8u+3)

Step-by-step explanation:

lmk if you want an explanation

6 0
2 years ago
Read 2 more answers
Which expressions are equivalent to (5g+3h+4)\cdot2(5g+3h+4)⋅2left parenthesis, 5, g, plus, 3, h, plus, 4, right parenthesis, do
hichkok12 [17]

Answer:

C  None of the above

Step-by-step explanation:

Here are the required options

Choose all answers that apply

A  (5g+3h).8  

B  (5g+3h).6  

C  None of the above

Given the expression;

(5g+3h+4).2

Expand

(5g+3h+4).2

= 2(5g+3h+4)

= 2(5g) + 2(3h) + 2(4)

= 10g+6h+8

Checking option A;

(5g+3h).8

Expand

= 8(5g+3h)

= 8(5g) + 8(3h)

= 40g+24h

Checking option B:

(5g+3h).6

Expand

= 6(5g+3h)

Using the distributive law;

= 6(5g) + 6(3h)

= 30g+18h

Since none of the expressions for A and B is equivalent to 10g+6h+8, hence <u>NONE of the options are correct</u>

6 0
3 years ago
Describe the shaded areas.​
melomori [17]

9514 1404 393

Answer:

  the difference of 2 or 3 rectangles

Step-by-step explanation:

In every case, the "shaded" area can be computed by finding the area of a "bounding" rectangle, and subtracting the areas of the rectangular cutouts that give the figure its shape.

(a) The cutout is the white space at upper right. (Insufficient dimensions are given.)

(b) The cutout is the white space at lower left. The bounding rectangle is 8×7, and the cutout is 4×3.

(c) The cutout is the rectangle in the middle. The bounding rectangle is 13×7, and the cutout is 4×1.

(d) The cutouts are the rectangles on either side. They could be considered as a single unit. The bounding rectangle is 20×25; the cutouts have a total width of 16 and a height of 20, so total 16×20.

(e) Similar to (d), the cutouts are the white spaces on either side. The bounding rectangle is 14×12. The cutouts total 12 in width and 3 in height, so total 12×3.

__

You will note in (d) and (e) that the dimensions of the cutouts have something in common with the dimensions of the bounding rectangle. This means the problem can be simplified a little bit by factoring out that common factor. In (e), for example, 14×12 -(12×3) = 12(14 -3) = 12×11

4 0
3 years ago
Parking Lot A has twice as many cars as Parking Lot B. After 10 cars draw away from Parking lot A, and 13 cars moved from parkin
charle [14.2K]

Answer:

The original number of cars in parking Lot A was 72 cars and the original number of cars in parking Lot B was 36 cars

Step-by-step explanation:

Let

x----> original number of cars in parking Lot A

y----> original number of cars in parking Lot B

we know that

x=2y ----> equation A

(x-10-13)=y+13 ----> equation B

substitute equation A in equation B and solve for y

(2y-10-13)=y+13

(2y-23)=y+13

2y-y=13+23

y=36 cars

Find the value of x

x=2y -----> x=2(36)=72 cars

therefore

The original number of cars in parking Lot A was 72 cars

The original number of cars in parking Lot B was 36 cars

4 0
3 years ago
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