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Tamiku [17]
3 years ago
11

olor{orange}\mathbb{QUESTION} " alt=" \huge \color{orange}\mathbb{QUESTION} " align="absmiddle" class="latex-formula">
\sqrt{32 + 64 - 16 - 8 - 4 - 4}
​
Mathematics
2 answers:
OLga [1]3 years ago
8 0

Answer:

\huge \color{orange}\mathbb{Answer:}

=\sqrt{32 + 64 - 16 - 8 - 4 - 4}=\sqrt{64}=\sqrt{8²}=±8 is your answer

deff fn [24]3 years ago
6 0

Step-by-step explanation: it's answer is 8

hope it is helpful to you

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2<br> -6x + 5y = 1<br> 6x + 4y = -10
Luba_88 [7]

Answer:

(-1,-1)

Step-by-step explanation:

finding y

   -6x + 5y = 1

 + (6x + 4y = -10)

---------------------------

              9y = -9

                y = -1

finding x

-6x + 5(-1) = 1

-6x - 5 = 1

    + 5 = +5

-6x = 6

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6 0
3 years ago
Suppose M is the midpoint of FG. Find the missing measure.<br><br><br><br> FM=12x−4, MG=5x+10
Dmitrij [34]

Answer:

FG = 17x - 6

Step-by-step explanation:

FG = 12x + 5x + 10 - 4

5 0
3 years ago
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Is 2y-4=10 a function
Oksana_A [137]
Yup yup yup. i think so
3 0
3 years ago
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Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
3 years ago
HELP image is provided
Hitman42 [59]

Answer:

yes

Step-by-step explanation:

angles z and b both have 2 congruent lines

angle y and a have one congruent line

and lines CA and XY have a congruent tick mark

5 0
2 years ago
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