(x^2−1)(3x−4)(3x+4) what is the product

Mathematics

1 answer:

Andrei [34K]2 years ago

6 0

Answer:

9x^4-25x^2+16

Step-by-step explanation:

(x^2−1)(3x−4)(3x+4)=(*)

(x^2−1)((3x)^2−4^2) =

(x^2 - 1)(9x^2-16)=

x^2*9x^2 - x^2*16 - 1*9x^2 +16=

9x^4-16x^2-9x^2+16=

9x^4-25x^2+16

(*) (A-B)(A+B) =A^2 - B^2

You might be interested in

X to the 2 power -6 when X = -14

riadik2000 [5.3K]

-14x-14 = 196 then subtract -6 from 196 because they'll cancel each other out. the answer is 190.

8 0

3 years ago

Solve the following equation and show all the steps to solving.

Bumek [7]

$\bf \cfrac{x}{x-2}+\cfrac{x-1}{x+1}=-1\impliedby LCD\to (x-2)(x+1)\\\\
-------------------------------\\\\
\cfrac{x(x+1)+(x-1)(x-2)}{(x-2)(x+1)}=-1
\\\\\\
x^2+x+x^2-3x+2=-1(x-2)(x+1)
\\\\\\
2x^2-2x+2=-1(x^2-x-2)\implies 2x^2-2x+2=-x^2+x+2
\\\\\\
3x^2-3x=0\implies 3x(x-1)=0\implies 
\begin{cases}
3x=0\implies &x=0\\
x-1=0\implies &x=1
\end{cases}$

8 0

2 years ago

Reduce to the lowest terms<br> 1. 4x^3 y^4 / -8xy^2 <br> 2. 3m^2-3n^2 / 6m+6n

lawyer [7]

1.
$\dfrac{4x^{3}y^{4}}{-8xy^{2}}=\dfrac{4}{-8}\cdot x^{3-1}y^{4-2}=\dfrac{-x^{2}y^{2}}{2}$

2.
$\dfrac{3m^{2}-3n^{2}}{6m+6n}=\dfrac{3}{6}\cdot \dfrac{(m+n)(m-n)}{m+n}=\dfrac{m-n}{2}$

3 0

3 years ago

Power Up Test Practice

omeli [17]

Answer: 26

Step-by-step explanation: Add all the booths together and you will get 300. You will get 300 because the t-shirts booth is $26. Now divide 300 by how many booths there are, which is six. And your mean will be 50.

6 0

1 year ago

5x - 4y + 8 ; x = 8 , y = 2.5

Mice21 [21]

It’s 38 :) I hope it helps

8 0

3 years ago

Read 2 more answers