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Lana71 [14]
3 years ago
11

-2+6x=12-x please help me solve this

Mathematics
2 answers:
vredina [299]3 years ago
6 0

=2

yeah that's just the answer lol

Sidana [21]3 years ago
5 0

Answer:

X=2

Step-by-step explanation:

-2+6x=12-x

add 2 to both sides

6x=14-x

now add 1x to both sides

7x=14

and finally divide both sides by 7 so you x is left alone

<h2>x=2</h2>

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Which comparisons are true? Choose all that apply. A. 7.34 &gt; 7.304 B. 1.628 &gt; 1.63 C. 4.05 &lt; 4.055 D. 9.103 &lt; 9.13 E
Nimfa-mama [501]

Answer:

The answers are A, C, & D.

Step-by-step explanation:

A: the 34 would have an imaginary 0 behind it, so then it would become 340, which is greater than 304.

B, C, D: same logic as A

6 0
3 years ago
Solve the equation
Klio2033 [76]

Answer:

x = 25

Step-by-step explanation:

.20x + .68(120 - x) = .54(120) (Distribute .68 to 120 and -x)

.20x + 81.6 - .68x = .54(120) (multiply .54 and 120)

.20x + 81.6 - .68x = 69.6 ( add .20x and -.68x)

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-.48x = -12 (divide -12 by -.48)

x = 25

4 0
4 years ago
What is the answer to this multiplication problem 650*3456
Roman55 [17]
650 * 3456 = 2,246,400 is the answer.
7 0
3 years ago
Read 2 more answers
First step for solving x²+2x-11=4
fenix001 [56]

Answer:

subtract 4 on both side.

5 0
3 years ago
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|x|, if x=10; .3; 0; −2.7; −9
alekssr [168]

Answer:

For \left | x \right | we will have positive values only.

\left | -2.7 |\right =2.7

\left | -9 |\right =9

Rest are positive so will give positive values out of the modulus function.

Step-by-step explanation:

The absolute value of any number is its positive value only.

As for example (-2.7) and (2.7) both are having equal distance from 0 in a number line, one on the left other on the right side of the number line but are equidistant from 0.

So absolute value of a number is its distance on number line from reference point 0.

One by one we will work with all of our question.

\left | 10 |\right =10

\left | 0.3 |\right =0.3

\left | 0 |\right =0

\left | -2.7 |\right =2.7

\left | -9 |\right =9

So we have to take the positive number out of the modulus function that is also called absolute value.

5 0
3 years ago
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