4 divided by 12 is 1/3.
So, she would sprinkle 1/3 of a gram on each cupcake.
The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
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There is one solution. The solution of the system is (9,-5)
Option A is correct.
Step-by-step explanation:
We need to solve the system of equations by elimination method
Rearranging the equations:
Eliminating y to find value of x:
Multiply eq(1) by 5 and eq(2) by 2 and add both equations:
So, value of x= 9
Eliminating x to find value of y:
Multiply eq(1) by 2 and eq(2) by 6 and subtract both equations:
So, value of y = -5
There is one solution. The solution of the system is (9,-5)
Option A is correct.
Keywords: Solving system of equations
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