No, you can't. If the denominator is greater than the numerator, that fraction's absolute value is always less than 1. If the numerator is greater than the denominator, that fraction's absolute value is always more than 1. Therefore, for both of them to be equal to each other, you are saying that a fraction that is less than 1 is equal to the fraction more than one. However, you can have a fraction with a larger denominator actually be of greater value than the one with the larger numerator. For example, -(9/8) vs -(8/9). -(9/8) has a greater numerator, yet -(8/9) is greater than it, despite having a larger denominator. Of course, this case can be written off as having the negative factored in with either the numerator with denominator, so it is easier to remember the rule above without the negative mumbo jumbo.
35
Explaination : 70 divided by 2 is 35
Eight ten-thousandths = 8*(1/10,000) = 8/10⁴ = 8 x 10⁻⁴.
Thirty-five million = 35*(1,000,000) = 35 x 10⁶
Therefore eight ten-thousandths of thirty-five million is
(8 x 10⁻⁴) * (35 x 10⁶)
= 280 x 10⁶⁻⁴
= 280 x 10²
= (2.8 x 10²) * 10²
= 2.8 x 10⁴
Answer: 2.8 x 10⁴
First know how many pounds are in a ton
there are 2000 pounds in a ton
so simply divide
7000/2000=3.5
So there are 3.5 tons of brick on the truck
Answer:
a) 4u + 2v = (8, 12, 14)
b) 2u - v = (0, 6, 1)
c) |u + 4v| = 16.9
Step-by-step explanation:
When we add/subtract vectors, we add/subtract their components. For example
a = (a1,a2,a3)
b = (b1,b2,b3)
a+b = (a1 + b1, a2 + b2, a3 + b3)
|a| is the modulus of vector a, given by
In this problem, we have that:
u = (1,3,2)
v = (2,0,3)
(a) 4u+2v
4u = 4(1,3,2) = (4,12,8)
2v = 2(2,0,3) = (4,0,6)
4u + 2v = (8, 12, 14)
(b) 2u-v
2u = 2(1,3,2) = (2,6,4)
v = (2,0,3)
2u - v = (0, 6, 1)
(c) |u + 4v|
u = (1,3,2)
4v = 4(2,0,3) = (8,0,12)
u + 4v = (9,3,14)
