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2 years ago

12

There are 23 boys and 35 girls on the school's track and field team. After q boy at random to represent the school for an event

becomes 2/5, find the value of q.

1 answer:

MA_775_DIABLO [31]2 years ago

4 0

Answer:the value of q is48

Step-by-step explanation:

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Solve the inequality.<br> 2(4+2x)≥5x+5<br> A. x≤−2<br> B. x≥−2<br> C. x≤3<br> D. x≥3

LenaWriter [7]

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Find the slope of the line that passes through the points (3, 6) and (5, 3).

FromTheMoon [43]

The slope of the line is -3/2

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3 years ago

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Represent each of the following variables in the appropriate letters.Next determine wether the variable has a fixed value or a c

Alex777 [14]

Step-by-step explanation:

a) Let 'm' represents score in a Mathematics test. The variable has a fixed value because the marks Sarah obtained in her test will not change

b) Let 'd' represent the distance between the Zen house and the school. The variable has a fixed value because by using the same route, the distance will always remain constant.

c) Let 't' represent the temperature on the summit of Mount Everest. The variable has a changed value because the temperature may alter depending on the time of day and also climatic conditions which will affect the temperature.

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2 years ago

A boat travels 33 miles downstream in 4 hours. The return trip takes the boat 7 hours. Find the speed of the boat in still water

Paha777 [63]

<u>Answer:</u>

Speed of the boat in still water = 6.125 miles/hour

<u>Step-by-step explanation:</u>

We are given that a boat travels 33 miles downstream in 4 hours and the return trip takes the boat 7 hours.

We are to find the speed of the boat in the still water.

Assuming $S_b$ to be the speed of the boat in still water and $S_w$ to be the speed of the water.

The speeds of the boat add up when the boat and water travel in the same direction.

$Speed = \frac{distance}{time}$

$S_b+S_w=\frac{d}{t_1}=\frac{33 miles}{4 hours}$

And the speed of the water is subtracted from the speed of the boat when the boat is moving upstream.

$S_b-S_w=\frac{d}{t_2}=\frac{33 miles}{7 hours}$

Adding the two equations to get:

$S_b+S_w=\frac{d}{t_1}$

+ $S_b-S_w=\frac{d}{t_2}$

___________________________

$2S_b=\frac{d}{t_1} +\frac{d}{t_2}$

Solving this equation for $S_b$ and substituting the given values for $d,t_1, t_2$ :

$S_b=\frac{(t_1+t_2)d}{2t_1t_2}$

$S_b=\frac{(4 hour + 7hour)33 mi}{2(4hour)(7hour)}$

$S_b=\frac{(11 hour)(33mi)}{56hour^2}$

$S_b=6.125 mi/hr$

Therefore, the speed of the boat in still water is 6.125 miles/hour.

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the small intestine is about 23 feet long while the large intestine is only 5 feet long what is the ratio of the large intestine

ioda

Answer:

it's answer is 4:1

Because length of small intestine is 6 m and length of large intestine is 1•5m

So 6/1•5 =4:1

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