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jasenka [17]
3 years ago
7

Cool Tees is having a Back to School sale where all t-shirts are discounted by 15%. Joshua wants to buy five shirts: one costs $

9.00, two cost $12.00 each, and two others cost $21.00 each. What is the cost of the shirts after the discount?
Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0

Answer:

$64.5745

Step-by-step explanation:

Marina CMI [18]3 years ago
3 0
The answer to your question is $64.5745
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What is the first step in solving: 14 + 2x - 3 = 43?
ch4aika [34]
D. Subtract 14

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3 0
3 years ago
A flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 18 feet mor
Aleksandr [31]

Answer:

42 ft, 60 ft, 84 ft

Step-by-step explanation:

let x be the shortest side , then the other 2 sides are 2x and x + 18, so

x + 2x + x + 18 = 186 , that is

4x + 18 = 186 ( subtract 18 from both sides )

4x = 168 ( divide both sides by 4 )

x = 42

Then lengths of sides are

x = 42 ft

2x = 2 × 42 = 84 ft

x + 18 = 42 + 18 = 60 ft

8 0
3 years ago
What is the solution to this equation?
sattari [20]

Answer:

Step-by-step explanation:

x -  9 = 17

x = 26

the answer is D

4 0
3 years ago
This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
4 0
3 years ago
Someone help.me find angle C and D<br>also this is in CIRCLE THEOREM lesson​
Artyom0805 [142]

Step-by-step explanation:

Opposite angles in a cyclic quadrilateral are supplementary.

Therefore 3c = 4d = 180°, c = 60° and d = 45°.

8 0
2 years ago
Read 2 more answers
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