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Tamiku [17]
2 years ago
9

The length of a rectangle is 9 inches more than half the width. Find the length if the perimeter is 60 inches.

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

Length = 10.435 inches

Step-by-step explanation:

Let the length be l

Let the width be w

Since the length is 9 inches more than half the width.

Then;

L = 0.5w + 9

Perimeter of a rectangle is;

P = 2Lw

Thus;

P = 2w(0.5w + 9)

Since perimeter = 60

Then;

2w(0.5w + 9) = 60

w² + 18w = 60

w² + 18w - 60 = 0

From quadratic formula;

w ≈ 2.87 in

L = 0.5(2.87) + 9

L = 10.435 in

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jok3333 [9.3K]

Answer:

The distance from Endnville to Concord = 14.8 miles

Step-by-step explanation:

∵ Westfalls is 7 miles South of Endnville

∵ Concord is 13 miles West of Westfalls

∵ South and West are ⊥

∴ The distance from Endnville to Concord = √(7)² + (13)²

                                                                      = 14.8 miles

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3 years ago
PLZ HELP ME IM GOING TO FAIL THEN PLZ A cyclist cycles a distance of 48 miles in a time of 3 hours.
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Answer:

her average speed is 16 miles per hour

Step-by-step explanation:

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Step-by-step explanation:

6 0
3 years ago
A square has an area of 144 sq. units. how long is its perimeter?
Arada [10]
Formula for Area of a square:

\boxed {\boxed {\text {Area = Length x Length}}}

Given that the area is 144 unit²:

\text {Length}^2 = 144

\text {Length} = \sqrt{144} = 12 \text { units}

Formula for Perimeter of a square:

\boxed {\boxed {\text {Perimeter = 4 x Length }}}

\text {Perimeter = } 4 \times 12 = 48 \text { units}


\boxed { \boxed { \text {Answer: The perimeter is 48 units.}}}


6 0
3 years ago
Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)
kifflom [539]

Answer:

\displaystyle y=\frac{2}{3}(x+5)+2

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

\displaystyle y=-\frac{3}{2}x+4

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

m_1.m_2=-1

Solving for m2:

\displaystyle m_2=-\frac{1}{m_1}

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\displaystyle m_2=\frac{2}{3}

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