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34kurt
3 years ago
10

Find 10 onomatopoeia words and use them to write your OWN onomatopoeia poem,

Mathematics
2 answers:
blondinia [14]3 years ago
3 0

Answer:

“Oh, the bells, bells, bells!

What a tale their terror tells

Of Despair!

How they clang, and clash, and roar!

What a horror they outpour

On the bosom of the palpitating air!

Yet the ear it fully knows,

By the twanging,

And the clanging,

How the danger ebbs and flows;

Yet the ear distinctly tells,

In the jangling,

And the wrangling.”

Step-by-step explanation:

Rus_ich [418]3 years ago
3 0

Bam!

went the branch in the night

Swoosh!

goes the wind out of sight

Boom!

says the thunder while it rains

Bang!

when the lightning hits the frame

Slosh!

muddy ground dirty feet

EEK!

screams the children ankle-deep

Splish!

goes the puddles under feet

Squeak!

goes the rubber boots

Ugh!

goes the parents when they're done

Snore!

goes the little tired ones

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Please please help I will give you alot of POINTS THIS IS A TRUE and FALSE SO HELP ME ASAP PLEASE THIS IS DUE IN LESS than a hou
adelina 88 [10]

Answer:

false

Step-by-step explanation:

cuz

3 0
3 years ago
Read 2 more answers
Choose all true statements.
serious [3.7K]

Answer:

Some rational numbers are natural numbers  

All whole numbers are integers  

Some integers are natural numbers.

Step-by-step explanation:


3 0
3 years ago
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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
What number u satisfies the equation sqrt{100u-100}=100?
kifflom [539]
The answer is 101
100 squared is 10,000
Then form an equation
100u-100=10,000
        +100    +100
100u=10,100
divide by 100 on both sides
and you get 101 as the answer
6 0
3 years ago
Read 2 more answers
PLEASE HURRY IM GIVING BRAINLIEST AND 50 POINTS!!! for the function g(x) = x - 2x^2, find g(-3) + 13
Inessa [10]

Hey there! I'm happy to help!

If we have g(-3) we plug -3 into our function as x.

-3-2(-3)²

-3-2(9)

-3-18

-21

g(-3) is -21, so now we just add 13.

-21+13=-8

The answer is -8.

Have a wonderful day! :D

5 0
3 years ago
Read 2 more answers
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