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Nuetrik [128]
3 years ago
11

A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the posit

ive x-axis. What are the x- and y-components of the vector?
Mathematics
1 answer:
trapecia [35]3 years ago
3 0

Answer:

F^{'}=(250\sqrt{3},250 })

Step-by-step explanation:

We have F´ =500 and \alpha=30º, so x and y components:

F´ = (F_{x} , F_{y}) this is

F_{x} = F^{'} *Cos\alpha

F_{y} = F^{'} *Sin\alpha  

F_{x} = F`*Cos\alpha =500*Cos30=500*\frac{\sqrt{3} }{2} =250\sqrt{3}

F_{y}=F*Sin\alpha  =500*Sin30=500*\frac{1}{2}=250;

Finally

F' = (250\sqrt{3} , 250)

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