Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
<span>the width of the cake pan can be found with the following formula
area = W x L=</span>432 in.2<span>
but L= 4/3W
so we have </span>
area = W x 4/3W=4/3W²=<span>432 in.2, and </span><span>W²=<span>(3/4)x 432 in.2, and W=18 in</span> </span>
Answer:
The second one is correct.
Answer:
12825$
Step-by-step explanation:
1 yard = 3 ft
we can convert each of the lengths from ft to yards
240 ft = 80 yards
285 ft = 95 yards
450 ft = 150 yards
150+150+95+80 = 475 yards
1 yard of fencing costs 27$ so we are going to multiply that by the total yards
475*27=12825$
