The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
To solve this equation from the information given above, I ordered it 5x+12=8x. To solve, I subtracted 5x from each side, canceling the 5x to your left, leaving only the number 12. 8x minus 5x equals 3x. Take 3x and divide on both sides. 3x/3x cancels the 3, leaving 12/3 equals 4. Finally, x equals 4.
Answer: Arun is now 20, Shree is 10 years old
Step-by-step explanation:
In the system of equations Arun's age is a. Shree is s
a = 2s .(current age equation) Subtract 5 from each for five years ago,
a-5 = 3(s-5) . Substitute 2s for a in the second equation
2s -5 = 3(s-5) distribute and reorganize
2s-5 = 3s -15 . 15 - 5 = 3s - 2s
10 = s . Substitute into the first equation to find a
a = 2(10)
a = 20
5 years ago Shree was 5 and Arun was 15
I^2 = (sqrt-1)^2 then the square cancels out so the answer is just
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