Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
I think “c” is the correct answer. I am not sure
Answer:
a) P=0.558
b) P=0.021
Step-by-step explanation:
We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.
The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:


b) The approximate probability that at least 9 carry the gene is:


