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3 years ago

Let f(x)=x+1 and g(x)=5x evaluate the composition (f•g)(-1)

Mathematics

1 answer:

MaRussiya [10]3 years ago

3 0

Answer:

$(f\circ g )(x) = -4$

Step-by-step explanation:

We have

$(f\circ g )(x) := f(g(x))$

Therefore,

$f(x)=x+1 \implies f(x)=g(x)+1$

So,

$(f\circ g )(x) = 5x + 1$

For $x = -1:$

$(f\circ g )(x) = 5(-1) + 1 = -5+1=-4$

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abruzzese [7]

Answer:

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Step-by-step explanation:

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3 years ago

Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5

liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

$ax^2+bx+c=0$

are

$\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0$

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

$a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}$

$\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

What is the difference between the following two regression equations? ModifyingAbove y with caret equals b 0 plus b 1 xy=b0+b1

Leona [35]

Answer:

A. The first equation is for sample data; the second equation is for a population.

Step-by-step explanation:

The first equation is y = $b_0 + b_1x$ , this is the equation for sample data as the intercept ( $b_0$ ) and the slope parameter( $b_1$ ) both are calculated then we have got this and these values are not taken as given.

The Second equation is $y = \beta _0 +\beta _1x$ , this is the equation for population data as we can't calculate these $\beta _0$ and $\beta _1$ as we take these values as given and also we do testing for $\beta$ parameter using t test and it is sure that testing is always done on population data not on sample data.

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