3 2/3 = 3x3=9+2=11/3
4 2/5= 4x5=20+2=22/5
Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic
p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
You can divide the figure as follows:
- A vertical rectangle, 5 meters tall and 2 meters wide, on the top right.
- A horizontal rectangle, 2 meters tall and 5 meters wide, on the bottom left
- A 2x2 meters square on the bottom right, where the two rectangles meet.
The area of the rectangles is 5x2=10 meters squared, while the area of the square is 2x2=4 meters squared.
So, the total area is 10+4=14 meters squared.
X would be equal to time and y be equal to distance
The y axis would be measuring distance and the x axis would be measuring time. Another name for a speed graph is the distance time graph. The y axis would be measuring the distance covered by the truck in meters and the x axis would be for the time it takes to reach that distance in second.
B) 2-6 would represent contact motion, meaning the vehicle is at rest. The time would be increasing from 2-6 to however the distance remains the same which is 20m
Answer:
-0.399
Step-by-step explanation:
f^-1(1024)=(2*1024-2/5)^-1= 0.000488
f(0.000488)=2*0.000488-2/5= -0.399
