Answer:
v is the wave speed in metres per second, m/s. f is the frequency in hertz, Hz. λ (lambda) is the wavelength in metres
Answer:
number line a
Step-by-step explanation:
-6x +18 < 30
-6x < 12
x> -2
i think it is EJ=JG
because EG not biects angle E, eg is not perpendicular with ff
<span> If </span>θ<span> is an acute angle in a right triangle </span>Cosecant<span> of </span>θ<span>, denoted </span>csc(θ<span>), is the ratio of the hypotenuse's length over the opposite side's length</span>
951 1404 393
Answer:
61.03 N at 35° above the horizontal
Step-by-step explanation:
The forces operate at right angles, so the Pythagorean theorem can be used to find the magnitude of the resultant:
||F1 +F2|| = √(50² +35²) = √3725 ≈ 61.03 . . . . newtons
The angle (α) relative to F2 can be found using the tangent relation.
tan(α) = 50/35
α = arctan(50/35) ≈ 55.008°
Then the angle relative to the horizontal reference line is ...
55.0° -20° = 35.0°
The resultant is about 61.03 N at an angle of 35° above the horizontal.
