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3 years ago

What is the value of the x varlable in the solution to the following system of equations?

2 answers:

8 0

Do elimination
2x + y = 3
x - y = 3
Add these
3x = 6
X = 2
Plug in 2 for x
4(2) + 2y = 6
8 + 2y = 6
2y = -2
X = 2, y = -1

Komok [63]3 years ago

6 0

Answer:

-1

Step-by-step explanation:

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Answer:

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The joint probability distribution will be c = 1/15

Step-by-step explanation:

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3 years ago

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The capacity of a beamer is 0.1 liter. convert this to milliliters

Vladimir [108]

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3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

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Answer:

1 conductors

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3 years ago

What is the sum of 9+10 (;

garri49 [273]

Answer:

19 or 21.

Step-by-step explanation:

I swear.

5 + 5 = 10

10 + 5 = 15

15 + 4 = 19

________________

9 + 9 = 18

18 + 10 = 28

28 - 5 = 23

There are two nines so

23 - 2 = 21

6 0

3 years ago