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Zepler [3.9K]
3 years ago
5

HELP ME !!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

Bye

Step-by-step explanation:

Figure it out yourself

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The position vector for a particle moving on a helix is
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Answer:

a) 25.15

b)

   x = 1

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Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

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And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

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Answer:

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