To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
Answer:
The probability that exactly two have flaws is P (x=2) = 0.2376
Step-by-step explanation:
Here
Success= p= 0.15
Failure = q= 0.85
total number= n= 8
Number chosen = x= 2
Applying the binomial distribution
P (x=x) = nCx p^x(q)^n-x
P (x=2) = 8C2 0.15 ²(0.85)^8
P (x=2) = 0.2376
The success is chosen about which we want to find the probability. Here we want to find the probability that exactly two have flaws so success would be having flaws therefore p = 0.15
Find the range of 5,3,1,1,3,3,4,4,4,1,1,4,2,2,5,5,5,2,5,5
ExtremeBDS [4]
Answer: 4
find the largest number (5) and take away the smallest (1)
5-1=4
