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amid [387]
3 years ago
11

Fill in the table using this function rule. y=-2x+3 × -2, -1, 0, 1

Mathematics
1 answer:
ycow [4]3 years ago
6 0

Answer:

If x = -2, -1, 0, 1, then (In this order) y = 7, 5, 3, 1

Step-by-step explanation:

If you put in each value of "x" into the equation, you'll get the appropriate "y".

y= -2(-2)+3

y= 4+3

y= 7

y= -2(-1)+3

y= 2+3

y= 5

y= -2(0)+3

y= 0+3

y= 3

y= -2(1)+3

y= -2+3

y= 1

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D 32 miles to the gallon
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4 0
3 years ago
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A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
A highway map of Ohio has a coordinate grid superimposed on top of the state. Springfield is at point (1, –4) and Columbus is at
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Rest Area=(4, -1.5)

The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.

d^2=(x2-x1)^2+(y2-y1)

d^2=(7-1)^2+(1--4)^2

d^2=36+25

d^2=61

d=√61  and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:

D=5.38√61 mi

D≈42.02mi  (to nearest hundredth of a mile)
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Answer:

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Step-by-step explanation:

Convert the speeds of Amir and Ryder to meters per second (m/s).

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Ryder:

930 cm/s = 9.30 m/s

9.30 m/s > 8.260 m/s, so:

Ryder ran approximately 1 meter per second faster than Amir.

3 0
3 years ago
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