Answer:
Step-by-step explanation:
Given that acceleration of an object is

is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0

So solution for distance is

A = base side=3
b= base side=5
c = base side=3
h= height=7-4=3
l= lenght=6
w= width=5
h= height=4
V= 1/4h√(-a⁴+2(ab)²+2(ac)²-b⁴+2(bc)²-c⁴) + l w h
V=12.44+ 120=132.44 unit³
First move the 14 over so 1/3s = 12 then do 12 divided by 1/3, that would be 36 so s=36