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amid [387]
2 years ago
11

Fill in the table using this function rule. y=-2x+3 × -2, -1, 0, 1

Mathematics
1 answer:
ycow [4]2 years ago
6 0

Answer:

If x = -2, -1, 0, 1, then (In this order) y = 7, 5, 3, 1

Step-by-step explanation:

If you put in each value of "x" into the equation, you'll get the appropriate "y".

y= -2(-2)+3

y= 4+3

y= 7

y= -2(-1)+3

y= 2+3

y= 5

y= -2(0)+3

y= 0+3

y= 3

y= -2(1)+3

y= -2+3

y= 1

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Let $P$ and $Q$ be constants. The graphs of the lines $x + 5y = 7$ and $15x + Py = Q$ are perpendicular and intersect at the poi
Marta_Voda [28]

Answer:

<em>(-3, -129)</em>

<em></em>

Step-by-step explanation:

Given

Two lines:

$x + 5y = 7$

$15x + Py = Q$

are perpendicular to each other and intersect at point (-8,3).

To find: (P, Q)

Solution:

The two lines intersect at (-8,3).

It means, the equation of line will be satisfied when we put value of x = -8 and y = 3

Putting in the second equation, we will get an equation in P and Q:

15\times (-8) + P \times 3 = Q\\\Rightarrow 3P = Q +120 ..... (1)

Given that two lines are perpendicular.

It means the product of their slopes will be equal to -1.

i.e. m_1\times m_2=-1

Slope of a line of the form ax+by+c=0 is given as:

m=-\dfrac{a}{b}

So, slopes of given lines are:

m_1=-\dfrac{1}{5}\\m_2=-\dfrac{15}{P}

Using the condition:

-\dfrac{1}{5}\times \dfrac{-15}{P}=-1\\\Rightarrow P = -3

Putting the value of P in equation (1):

\Rightarrow 3\times (-3) = Q +120 \\\Rightarrow Q = -9-120 = -129

So, answer is <em>(-3, -129)</em>

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3 years ago
Is the following a function?
saw5 [17]

Answer:

yes

Step-by-step explanation:

For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship

This graph displays this feature and is a function.


5 0
3 years ago
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Please help with 7 and 8
Serhud [2]

For #7 - part a: greatest common factor (GCF) is 5.

Part b: cross out everything BUT 10 & 20.

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