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postnew [5]
3 years ago
5

5/12=10/? Someone please help

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0

Answer:

10/24

Step-by-step explanation:

5/12 = 10/?

Find the scale factor: It is 2 because the 5 is multiplied by 2 to get 10.

12 x 2 = 24

nasty-shy [4]3 years ago
4 0

Answer:

0.4167

Step-by-step explanation:

hope i help

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The hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long. What is the len
alexandr1967 [171]
First. we use the Pythagorean theorem:
a {}^{2} +  b {}^{2} =  c {}^{2}
Add the numbers in
{30}^{2}  +  {b}^{2}  =  {50}^{2}
start simplifying
{b}^{2}  = 1600
b = 40

So, the leg has a length of 40 mm.
6 0
4 years ago
50b + 3f = 27<br> (b + f = 16) How do you solve b and f?
Juli2301 [7.4K]

Answer:

b= −3 /50 f+ 27/ 50

f= −50 /3 b+9

Step-by-step explanation:

Let's solve for <em>b</em>.

50b+3f=27

Step 1: Add -3f to both sides.

50b+3f+−3f=27+−3f

50b=−3f+27

Step 2: Divide both sides by 50.

50b /50 = −3f+27 /50 b= −3 /50 f+ 27 /50

Let's solve for <em>f</em>.

50b+3f=27

Step 1: Add -50b to both sides.

50b+3f+−50b=27+−50b

3f=−50b+27

Step 2: Divide both sides by 3.

3f /3 = −50b+27 /3

f= −50 /3 b+9

brainliest please?

8 0
3 years ago
Help solve for number 6 please !!<br> :)
Semenov [28]

Answer:

x: {-3, 5}

Step-by-step explanation:

Step 1. Find least common denominator

Step 2. Multiply missing factors on top AND bottom

Step 3. Combine like terms

Step 4. Simplify (get rid of denominator)

Step 5. Solve for x

\frac{x}{x-5} +\frac{3}{x+2} =\frac{7x}{x^2-3x-10}            LCD = x^2-3x-10   OR  (x-5)(x+2)

\frac{x}{x-5}(\frac{x+2}{x+2})  +\frac{3}{x+2}(\frac{x-5}{x-5})  =\frac{7x}{x^2-3x-10}

\frac{x(x+2)}{(x-5)(x+2)} +\frac{3(x-5)}{(x+2)(x-5)} =\frac{7x}{(x-5)(x+2)}

\frac{x(x+2)+3(x-5)}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+2x+3x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+5x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

x^2+5x-15=7x

x^2-2x-15

(x-5)(x+3)

<u>x = -3, 5</u>

8 0
3 years ago
Which of the following is NOT a solution to the inequality graphed below?  
podryga [215]
 i think the answer is  (0,-3)
4 0
3 years ago
Need help #3. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Sunny_sXe [5.5K]

Answer:

A

Step-by-step explanation:

We are given a right triangle with a base of <em>x</em> feet and a height of <em>h</em> feet, where <em>x</em> is constant and <em>h</em> changes with respect to time <em>t</em>.

The angle in radians is defined by:

\displaystyle \tan(\theta)=\frac{h}{x}

And we want to find the relationship that describes dθ/dt and dh/dt.

So, we will differentiate both sides with respect to <em>t</em> where <em>x</em> is a constant:

\displaystyle \frac{d}{dt}[\tan(\theta)]=\frac{d}{dt}\Big[\frac{h}{x}\Big]

Differentiate. Apply the chain rule on the left. Again, remember that <em>x</em> is just a constant, so we can move it outside the derivative operator. Therefore:

\displaystyle \sec^2(\theta)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

Since we know that tan(θ)=h/x, <em>h</em> is the opposite side of our triangle and <em>x</em> is the adjacent. Therefore, by the Pythagorean Theorem, our hypotenuse will be:

\text{Hypotenuse}=\sqrt{h^2+x^2}

Since secant is the ratio of the hypotenuse to adjacent:

\displaystyle \sec(\theta)=\frac{\sqrt{h^2+x^2}}{x}

So:

\displaystyle \sec^2(\theta)=\frac{x^2+h^2}{x^2}

By substitution, we have:

\displaystyle \Big(\frac{x^2+h^2}{x^2}\Big)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

By multiplying both sides by the reciprocal of the term on the left:

\displaystyle \frac{d\theta}{dt}=\frac{1}{x}\Big(\frac{x^2}{x^2+h^2}\Big)\frac{dh}{dt}

Therefore:

\displaystyle \frac{d\theta}{dt}=\frac{x}{x^2+h^2}\frac{dh}{dt}

Our answer is A.

3 0
3 years ago
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