Answer:
Area: 272ft²
Volume = 82.6236447189ft³
Step-by-step explanation:
AREA
The area of a square pyramid is found by combining the area of the base and the area of the triangular faces:
Area of base = area of square = L² = 8² = 16ft²
Area of one triangular face = (1/2)bh = (1/2)(8)(16) = 64ft²
There are four triangular faces so the total area = 16+4(64)= 16+256= 272 ft²
VOLUME
The volume of a square pyramid = (a²)(h/3), where a is the length of the base and h is the length from the top of the pyramid to the middle of the square.
We are given a, but not h. To find h, we must imagine a right-angled triangle within the pyramid, where 16ft is the hypotenuse, h is the height and the base is half of a (since the base is a square and the distance is from the edge to the middle). We can then use pythagorus's theorem to find h:
A²=B²+C²
16²=(8/2)²+h²
256=16+h²
h=√240
h=15.4919333848ft
Knowing h, we can find the volume:
Volume = (a²)(h/3)
Volume = (8²)(15.4919333848/3)
Volume = (16)(5.16397779493)
Volume = 82.6236447189ft³
Answer:
a. true
b. true
c. True
Step-by-step explanation:
a. The domain of a relation includes all possible set of data that are the x-values. Therefore, the domain of the relationship given would be: {2, 3, 5, 6}.
a is True.
b. The range includes all corresponding y-values. Therefore,
Range would be {1 4, 5, 7}
b is Tire.
c. There's 5 on both range and domain.
c is hungry.
Answer: 
Step-by-step explanation:
You did great until you expanded (3 - √5)². <em>You forgot the middle term</em>
Answer:
D
Step-by-step explanation:
