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3 years ago

1. Find the sum of the series . 15 show your work

Mathematics

2 answers:

Taya2010 [7]3 years ago

6 0

Answer:

b. 225

Step-by-step explanation:

i took the exam

tia_tia [17]3 years ago

4 0

Answer:

225

Step-by-step explanation:

15(1+15/2) *2= 240-15=225

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Find the solution of the system of equations.<br><br> -x+2y=-15<br> 8x-2y=-20

Grace [21]

Answer:

the answer is (-5,-10)

hope this helps :)

8 0

3 years ago

The Bill for dinner at Dave and Busters last night was $62.20. The waiter received an 18% tip. How much of a tip did the waiter

notsponge [240]

11.196 or 11.20 is the answer

3 0

3 years ago

Help answer both plz!

Sphinxa [80]

Answer:

3.6666 (I didn't round)

Repeating decimal

Step-by-step explanation:

We know that

2/3

is the same as

2÷3

Therefore:

3 2/3 = 3+(2÷3) = 3 + 0.6666 =3.6666

A repeating decimal is one that keeps going and repeats a pattern. This is decimal keeps going and repeats a pattern so it is a repeating decimal.

A terminating decimal is one that terminates or ends. This decimal does not terminate or end. It keeps going.

Hope this helped.

6 0

3 years ago

What is the unit ratio for a button of 16 grams and 2 milliliters?

Reika [66]

Answer:

The unit ratio would be 8 grams per milliliters

Step-by-step explanation:

Since, the unit ratio is a fraction with denominator 1,

In other words, the amount of one quantity in unit amount of other quantity is called unit rate or unit ratio.

Here, the amount first quantity = 16 grams,

The amount of second quantity = 2 milliliters,

Thus, unit ratio = $\frac{\text{First quantity}}{\text{Second quantity }}$

$=\frac{16}{2}$ = 8 grams per milliliters

6 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

1 year ago