For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
let the numbers be x and y then by given conditions:
x + y = 10 ….. eq 1
and
xy = 9….. eq 2
from eq 2. y = 9/x
put this in eq. 1
x + 9/x = 10
x + 9= 10x
x = 1
now,
xy = 9put value of x
y = 9
Step-by-step explanation:
Hope it is helpful....
5 wholes = 5
2 fifths = 2/5
5 - 2/5 = 4 3/5 (4 and 3 fifths)
Answer = 4 3/5
Check work:
4 3/5 + 2/5 = 5 (wholes)
If a = 10, then the equation would be 10+6.
The answer would be 16.
Hope this helps! :D
The values that make the denominator zero are not in the domain.
x²- 4x - 12 = 0
(x - 6)(x + 2) = 0
Answer: 6, -2
