So when one goes up, the other goes down. This is an inverse equation.
An inverse equation looks like this: y = 1/x
In this case, when parking fee (f) decreases, cars (c) increase.
You know which side to put each variable on using the chart they gave you.
f | c
20.00 15 (20.00 = x/15) x=300
30.00 10 (30.00 = x/10) x=300
So your equation in this case is f = 300/c
Knowing that, plug in the fee of 6.00
6 = 300/c Multiply both sides by c.
6c = 300 Divide both sides by 6.
c = 50 cars
Answer:
20.2 mm.
Step-by-step explanation:
2*2 + 2*8.1
= 4 + 16.2
= 20.2 mm.
Answer:
-2<x≤5
Step-by-step :
-1<x+1≤6 So fisrt what every we do to one side we must do to the other. In this case it's a bit different since we are dealing with inequalities.
-1<x+1≤6 I would start off by isolating x in the middle.
-1<x+1≤6 I subtracted 1 from all three sides.
-1 -1 -1
Now your equation should look like this:
-2<x≤5 Now there is really nothing much we can do here since we were just trying to get x by its self.
Answer : -2<x≤5
Answer:
64
Step-by-step explanation:
I did 90-26 I hope that’s what you’re looking for :))
1. Domain.
We have
in the denominator, so:
![x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\ (x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}](https://tex.z-dn.net/?f=x%5E2-2x-3%5Cneq0%5C%5C%5C%5C%28x%5E2-2x%2B1%29-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-2%5E2%5Cneq0%5Cqquad%5Cqquad%5B%5Ctext%7Buse%20%7Da%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D%5C%5C%5C%5C%28x-1-2%29%28x-1%2B2%29%5Cneq0%5C%5C%5C%5C%0A%28x-3%29%28x%2B1%29%5Cneq0%5C%5C%5C%5C%5Cboxed%7Bx%5Cneq3%5Cqquad%5Cwedge%5Cqquad%20x%5Cneq-1%7D)
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
