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maks197457 [2]
2 years ago
6

A container of orange juice contains 6 3/8 of juice. Jasmine used 3 6/8 ounces to make punch for a party,how many ounces are are

left?
Mathematics
1 answer:
mel-nik [20]2 years ago
5 0

Answer:

2 5/8 ounces of juice are left.

Step-by-step explanation:

6 3/8 - 3 6/8 =

  • 51/8 - 30/8 (Converted into improper fractions.)
  • 51/8 - 30/8 = 21/8
  • 21/8 = 2 5/8 (Converted improper fraction into a mixed fraction.)
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Answer:

a) volume = 321.55 in³

Step-by-step explanation:

volume = 4/3πr³ = 4/3(3.14)4.25³) = 321.55 in³

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3 years ago
Identify the cross section of the solid shown in the diagram
Ainat [17]

Answer:

B. Quadrilateral

Step-by-step explanation:

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3 years ago
Karl drove 619.5 miles. For each gallon of gas, the car can travel 41 miles. What is a reasonable estimate of the number of gall
dusya [7]

Answer:

15

Step-by-step explanation:

Calculation for What is a reasonable estimate of the number of gallons of gas Karl used

Estimated number of gallons used=619.5 miles/41 miles

Estimated number of gallons used=15

Therefore the reasonable estimate of the number of gallons of gas Karl used is 15

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3 years ago
The difference of d minus 3 divided by 2?​
Allisa [31]

\text{Hey there!}

\text{What is the difference of d minus 3 divided by 2?}\\\\\text{Difference means subtract/subtraction}\\\\\text{Minus would also be subtraction}\\\\\text{Divided by is division}\\\\\text{d would be the start of the problem}\\\\\text{the 3 divided by 2 would be on the right side ( the second part of the equation)}\\\\\boxed{\boxed{\bf{\ Answer:: d-\dfrac{3}2{}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day}\\\\\\\frak{LoveYourselfFirst:)}

6 0
2 years ago
I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
2 years ago
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