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2 years ago

13

Find the slope of the line that contains the points. (3, 8);(4, -2)

1 answer:

Goshia [24]2 years ago

5 0

Answer:

Is -6

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Over the last 3 years, salesperson A has earned twice as much as salesper B who in turn has averaged 50% more than salesper C. T

bekas [8.4K]

<span>A has earned twice as much as B so: A=2B
B has averaged 50% more than C so: B=C+0.5C
Combined is 220K, So A+B+C=220,000

The last equation can be re-written as:
2B+1.5C+C=220K
AND since A=2B, it can be rewritten again as:
3C+1.5C+C=220K

Now you can get C finally, since B=1.5C you can get B, then to get the average, just divide that by 3 (years) and you should be done.
So B = 60000 for 3 years</span>

4 0

3 years ago

Read 2 more answers

The answers to these questions

I am Lyosha [343]

Answer:

The formula to find the radius is diameter/pie. Also, it does not show the formula that they are asking.

Step-by-step explanation:

8 0

3 years ago

What is 10 to the second power as a decimal

natka813 [3]

Answer:

0.01

Step-by-step explanation:

If you convert 10 into a decimal it's just 0.1, multiply 0.1 by itself only one time because the exponent is 2 and you get 0.01

7 0

3 years ago

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What is the value of 7 + (-3) - 3 - 7 pls help thanks!!!

Citrus2011 [14]

Answer:

-6

Step-by-step explanation:

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3 years ago

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =

DanielleElmas [232]

Answer:

$c = 5$

Step-by-step explanation:

Given

$f(c) = M$

$f(x) = x^2 - x + 1$

$Interval: [1,8]$

$M = 21$

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

$f(x) = x^2 - x + 1$

$f(1) = 1^2 - 1 + 1$

$f(1) = 1$

$f(x) = 8^2 - 8 + 1$

$f(x) = 57$

$1 \le M \le 57$

$1 \le 21 \le 57$

M is within range.

Solving further:

We have:

$f(c) = f(x) = M$

$f(x) = 21$

Substitute 21 for f(x) in $f(x) = x^2 - x + 1$

$21 = x^2 - x + 1$

Express as quadratic function

$x^2 - x + 1 - 21 = 0$

$x^2 - x - 20 = 0$

Expand

$x^2 + 4x - 5x - 20$

$x(x+4)-5(x+4)=0$

$(x - 5)(x+4) = 0$

$x - 5 = 0$ or $x + 4= 0$

$x = 5$ or $x = -4$

The value of $x = -4$ is outside the $Interval: [1,8]$

So:

$x = 5$

$f(c) = f(x) = M$

$f(c) = f(5) = 21$

By comparison:

$c = 5$

4 0

2 years ago