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Gala2k [10]
3 years ago
11

A constant net force of 345 N is applied to slide a heavy stationary

Physics
1 answer:
liubo4ka [24]3 years ago
4 0

Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

P=F*t

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

P=345*1.5\\P=517.5[kg*m/s]

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A small metal sphere weighs .28 N in air and has a volume of13
Ray Of Light [21]

To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

W_T = W_A + F_B

Here

W_T= True Weight

W_A= Apparent Weight

F_B= Buoyant Force

If we seek to find the apparent weight we will have to,

W_A = W_T-F_B

W_A = 0.28N - V\rho g

Remember that

V = Volume (Volume Sphere)

\rho= Density (At this case water density)

g = Gravitational acceleration

W_A = 0.28N - (13*10^{-6}m^3)(1000kg/m^3)(9.8)

W_A = 0.1526N

Therefore the apparent weight will be 0.1526N

5 0
4 years ago
Ethnocentrism can lead to all the following except __________. A. tolerance B. stereotypes C. racism D. discrimination
lara [203]
A. Tolerance. When you have an "Us vs Them" mentality it can never lead to acceptance.
4 0
4 years ago
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Which is not a characteristic of chemical energy? A. chemical change B. breaking bonds C. splitting nuclei D. reacting substance
Delvig [45]

The correct answer is C. Splitting Nuclei.

Splitting nuclei is not a characteristics of chemical energy.

Chemical energy is termed as the energy which results when there is chemical reaction. Chemical energy is being stored in molecules which makes substance and bonds of atoms.

In order for our bodies to function well they need chemical energy. During photosynthesis plants perform chemical reaction each and every day.

3 0
3 years ago
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The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.
oksano4ka [1.4K]

Answer:

i = 2.84 \times 10^{-3} A

Explanation:

As we know that current density is ratio of current and area of the crossection

now we have

J = \frac{di}{dA}

so the current through the wire is given as

i = \int J dA

now we have

i = \int_{0.921R}^R J dA

here we have

J = (3.25 \times 10^8)r^2

now plug in the values in above equation

i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr

now we have

i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr

i = (2.04 \times 10^9) \frac{r^4}{4}

now plug in both limits as mentioned

i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})

i = (2.04\times 10^9)(0.07 R^4)

here R = 2.11 mm

i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)

i = 2.84 \times 10^{-3} A

8 0
3 years ago
Whats a peer review?
Goryan [66]
B is the answer to your question
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