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guajiro [1.7K]
4 years ago
15

Ceres, the largest asteroid known, has a mass of roughly 8.7 x1020 kg. If Ceres passes within 12,000km of the spaceship (2.75e4k

g) in which you are traveling, what force does it exert on the spaceship?
Physics
1 answer:
Nataly [62]4 years ago
5 0

Answer:

11.1 N

Explanation:

The gravitational force between the asteroid and the ship is given by:

F=G\frac{mM}{R^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M=8.7\cdot 10^{20} kg is the mass of the asteroid

m=2.75\cdot 10^4 kg is the mass of the spaceship

R=12,000 km=1.2\cdot 10^7 m is the distance between the asteroid and the spaceship

Substituting numbers into the equation, we find the force

F=(6.67\cdot 10^{-11})\frac{(2.75\cdot 10^4 kg)(8.7\cdot 10^{20} kg)}{(1.2\cdot 10^7 m)^2}=11.1 N

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All matter is made up of subatomic particles that contain atoms.TrueFalse
antiseptic1488 [7]

All matter is made up of subatomic particles that contain atoms. This is false statement.

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1 year ago
Which of the following is an observation and not an interference ​
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Hope this helps :)

4 0
3 years ago
A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac
Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\

<u>m = 2.2 x 10⁻⁴ kg = 0.22 g</u>

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