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3 years ago

4/7 is equal to 1 or bigger or smaller

1 answer:

5 0

4/7 is smaller than 1.

In order for 4/7 to be equal to 1. Then it would have to be 7/7 (1) as well.

For 4/7 to be bigger than 1. Then 4/7 has to be bigger than 1 as a number. This could be 1 1/3 or 2 4/7

Final Answer:

4/7 < 1

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artcher [175]

Answer:

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3 years ago

What is the improper fraction for 8 and 3/47

erastovalidia [21]

Answer:

379/47

Step-by-step explanation:

1. Simplify

2. Reduce fraction to lowest terms

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2 years ago

Read 2 more answers

SOMEONE HELP ME PLSSS!

Tomtit [17]

Answer:

y is 1 and x is 4

Step-by-step explanation:

becasue the y intercepts at 1 and the x intercepts at 4

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2 years ago

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Find the L.C.M. of: a2 + 2a +1, a? + 3a + 2

MArishka [77]

Step-by-step explanation:

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2 years ago

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago