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tekilochka [14]
3 years ago
10

When plotting points on the coordinate plane below, which point would lie on the x-axis?

Mathematics
2 answers:
babunello [35]3 years ago
8 0
Awnser is 6,0!!!!!!!!!!!!!
ZanzabumX [31]3 years ago
3 0

Answer: (6,0)

Coordinate points are always written in pairs of the x- and y-coordinate: (x, y). Knowing this, the point would need to have a y-value of 0 in order to lie on the x-axis (otherwise, it would be on a random spot on the grid). The only coordinate point with a y-value of 0 is (6, 0). Therefore, the coordinate point (6, 0) lies on the x-axis.

Please refer to the attached graph below to see all the coordinate points.

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At the bargain store , Tanya bought 3 items that each cost the same amount. Tony bought 5 items that each cost the same amount b
Afina-wow [57]

Answer:

"Tanya bought 3 items that each cost the same amt"

"Let x represent the cost of one of Tanya's items"

  So, Tanya bought 3 items, costing x+x+x = 3x

  Note that (number of items)*(cost per item) = (number of items)*(cost/item) = cost,   [item cancels out]

 

"Tony bought 4 items that each cost the same amt, but each was $2.25 less than the items Tanya bought."

 The cost for Tony's items was:  (x-2.25)+(x-2.25)+(x-2.25)+(x-2.25) = 4*(x-2.25)

 

"Tanya and Tony paid the same amt. of money"

   This is an equation (the same amount means equals)

    Tanya's cost = Tony's cost

a.) Write an equation. Let x represent the cost of one of Tanya's items

          3x      =     4(x-2.25)

 

Now, the math:

b.) Solve the equation. Show your work.

          3x      =     4(x-2.25)

          3x  =  4x - 9.00                 [distributive principle; multiply]

         -x = -9.00                      [subtract 4x from both sides; option, could instead add 9.00, then subtract 3x from both sides, getting 9.00=x]

          x = 9.00           [multiply both sides by (-1)]

                 [note:  to "solve for x" means to find the value(s) of x that make the equation true,

                          so let's see if it is true --]

c.) Check your solution. Show your work.

  Is              3x      =     4(x-2.25), when x=9.00    ?

          3(9.00) = 4(9.00-2.25)    ?

           27.00 = 36.00 - 9.00    ?

             27.00 = 27.00    ?yes

 

d) State the solution in a complete sentence.

     The problem started with:  "Tanya bought 3 items that each cost the same amt. Tony bought 4 items that each cost the same amt, but each was $2.25 less than the items Tanya bought. Both Tanya and Tony paid the same amt. of money."

     I would write:   "Tanya bought 3 items, each costing $9.00.  Tony bought 4 items, each costing $6.75.  Tanya and Tony each paid $27.00."  

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
What is the missing dimention with a cilinder with base as d and the height as 14 and it has a volume of 7433 in 3
Korolek [52]

Answer:

26in

Step-by-step explanation:

Volume of a cylinder = πr²h

Given

height h = 14in

Volume = 7433in³

Required

base d = 2r

r is the  radius

get the radius r

7433 = 3.14 * 14r²

7433 = 43.96r²

r² = 7433/43.96

r² = 169.08

r = 13.00

Since the base d = 2r

d = 2(13)

d = 26in

Hence the base of the cylinder is 26in

4 0
3 years ago
10 less than the sum of two consecutive numbers
damaskus [11]
The consecutive numbers 5and 6 equal 11 is that what yr asking
3 0
4 years ago
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Select all pairs of numbers that have a least common multiple of 30.
ddd [48]

5 and 6  and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3:  1 \times 3

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

               2 \times 3=6

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5:  1 \times 5

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

                     5 \times 2 \times 3=30

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3:  1 \times 3

Prime factorization of 10:  2 \times 5

Using all prime numbers found as often as each occurs most often we take

                    5 \times 2 \times 3=30

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5:  1 \times 5

Prime factorization of 10: 2 \times 5

Using all prime numbers found as often as each occurs most often we take

                       5 \times 2=10

Therefore LCM (5, 10) = 10

8 0
3 years ago
I'd really appreciate it if someone could help me with these square problems :/
adelina 88 [10]
I would but I don’t want to ;/
3 0
3 years ago
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