Consider the function c(x)=(x+3) (x-5)2 what are the zeros of c(x)
1 answer:
Answer:
The zeroes would be -3 and a double root at 5.
Step-by-step explanation:
We can find this by first expanding the function.
c(x) = (x + 3)(x - 5)^2
c(x) = (x + 3)(x - 5)(x - 5)
Then we can solve for the zeroes by setting each parenthesis equal to 0 and solving.
x + 3 = 0
x = -3
x - 5 = 0
x = 5
x - 5 = 0
x = 5
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