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Tanya [424]
2 years ago
15

Write a quadratic equation with 7 and as its roots. Write the equation in the form ax^2+ bx + C = 0,

Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0
X^2 - 37/5x + 14/5
.
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How would the expression x^3-8 be written using difference of cubes
ludmilkaskok [199]

we can use formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can compare

we get

a=x

b=2

now, we can plug that in formula

and we get

x^3-2^3=(x-2)(x^2+2x+2^2)

now, we can simplify it

x^3-8=(x-2)(x^2+2x+4)...........Answer

4 0
3 years ago
Read 2 more answers
My house is two blocks west and 5 blocks north of my school. My friends house is 8 blocks east and one block south of the school
insens350 [35]
16 blocks.
You drive 2 blocks west and 5 blocks North to get to school.
You then have to drive 8 blocks east and 1 block south to get to your friends house.
They’re all different directions so just add them all up. You get 16
3 0
3 years ago
Mathematics I need help
Mkey [24]

Answer:

The answer is b

Step-by-step explanation:

0.63-0.2=0.43

8 0
2 years ago
What is the value of X?
antiseptic1488 [7]
First you need to find the 3rd angle of the triangle
180 - 86 - 46 = 48

and then subtract the answer by 180 (because it’s a straight line)
180 - 48 = 132

so 132
8 0
3 years ago
If i=Square root of -1, what is the value of i^3?<br> A.-1<br> B.i<br> C.1<br> D.-i
madam [21]
 First we are going to reesribir the inaginario number:
 i = root (-1)
 i = (- 1) ^ (1/2)
 Then, we have to
 By properties of exponents:
 i ^ 3 = i ^ 2 * i
 Substituting the value of i:
 i ^ 3 = ((- 1) ^ (1/2)) ^ 2 * i
 Applying properties of exponents:
 i ^ 3 = ((- 1) ^ (1/2)) * ((- 1) ^ (1/2)) * i
 i ^ 3 = ((- 1) ^ ((1/2) + (1/2)) * i
 i ^ 3 = ((- 1) ^ ((2/2)) * i
 i ^ 3 = ((- 1) ^ (1) * i
 i ^ 3 = -1 * i
 i ^ 3 = - i
 Answer:
 D.-i

8 0
3 years ago
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