Answer:
13. is Option J) all of the above
and 14 I'm not completely sure but I think its option D.
Answer:
Medical Definition of erythrocytopenia
: deficiency of red blood cells. — called also erythropenia.
Explanation:
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Answer:
Mitochondria is the organelle where cellular respiration takes place. Cellular respiration can be described as a process in which oxygen and glucose are converted into carbon dioxide and water along with the release of ATP. This reaction can be written as:
Glucose + Oxygen → Carbon dioxide + Water + ATP molecules
C6H12O6 + 6O2→ 6CO2 + 6H2O + ATP
The ATP made can be broken down so that energy is released.
ATP + H2O → ADP + Pi + free energy
The amount of oxygen produced can be quantified in order to determine the rate of photosynthesis. Elodea leaves are divided into little pieces, and the cut ends are put into the funnel's stem.
<h3>What did Elodea's bubbles in this experiment represent?</h3>
The bubbles that you observe rising from an elodea cutting's leaves are actually a result of the photosynthesis process. In some types of algae and in plants, photosynthesis takes place. In the process, light energy is changed into a sort of chemical energy that is then stored as sugar.
<h3>What substance did we use to examine whether photosynthesis existed in Elodea?</h3>
To test whether photosynthesis and/or other processes are occurring, you will conduct experiments using the dye Phenol Red in this exercise. In Elodea plants, cellular respiration is taking place. The experiments look into how light affects these processes.
To know more about photosynthesis visit:-
brainly.com/question/1388366
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Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
