All categories

1 year ago

What is the area of the circle?

Mathematics

1 answer:

AlexFokin [52]1 year ago

4 0

Answer:

530.93

Step-by-step explanation:

area of a circle = πr²

where r = radius

here we are given the diameter

to convert to radius , we divide by 2

so radius = 26 / 2 = 13

so we have A = πr²

==> plug in r = 13

A = π13²

==> evaluate exponent

A = 169π

==> multiply 169 and π

A = 530.93 ( approximately )

You might be interested in

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

2 years ago

What is the equation of the trend line?<br> Enter your answers in the boxes.<br><br> K = _J +_

MrRissso [65]

The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0

Thus, the equation of the trend line, in variables K and J, is

K = 2J + 28

8 0

2 years ago

Please help as soon as possible!

AnnZ [28]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 6) and (x₂, y₂ ) = (8, 4)

m = $\frac{4-6}{8-3}$ = - $\frac{2}{5}$ , hence