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lidiya [134]
3 years ago
6

Is the relationship shown by the data linear? If so, model the data with an equation.

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:

4th option

Step-by-step explanation:

The relationship is linear,

putting the value of x in the right side of the equation of option 4, you'll get the value of the left side

putting, x=1

y+4=-1/2(x-1)

y=-1/2(1-1)-4

y=-4

putting, x=7

y+4=-1/2(7-1)

y=-1/2(6)-4

y=-6/2-4

y=-3-4

y=-7

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Given limit of f (x) = 4 as x approaches 0. what is limit of one-fourth left-bracket f (x) right-bracket superscript 4 baseline
Otrada [13]

The limit of the given function if \lim_{x \to 0} f(x)=4 is 64

<h3>Limit of a function</h3>

Given the following limit of a function expressed as;

\lim_{x \to 0} f(x)=4

We are to determine the value of the function

\frac{1}{4}  \lim_{x \to 0} [f(x)]^4


This can also be expressed as

\frac{1}{4}  \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64

Hence the limit of the given function if \lim_{x \to 0} f(x)=4 is 64

Learn more on limit of a function here: brainly.com/question/23935467

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4 0
2 years ago
Select one answer choice For part A and select one answer choice for part B
sweet [91]

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6 0
3 years ago
Solve question in image (yr 8 math, 40 pt)
Nady [450]

Answer:

y = 3

Step-by-step explanation:

(5y - 3)/4 + 6 = 3y

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Check.

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7 0
2 years ago
Read 2 more answers
3. Janet is flying a kite on a string that is 75m long. The kite is 62m above the ground. Estimate the distance between Janet an
konstantin123 [22]
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62. 
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem.  I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
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3 0
3 years ago
To the nearest tenth, what is the perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)?
katovenus [111]

9514 1404 393

Answer:

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  d = √((x2 -x1)^2 +(y2 -y1)^2)

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For the last and first points, ...

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Then the sum of the side lengths is ...

  5.83 +8.06 +6.40 = 20.29 ≈ 20.3

The perimeter of the triangle is about 20.3 units.

7 0
3 years ago
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