The limit of the given function if  is 64
 is 64
<h3>Limit of a function</h3>
Given the following limit of a function expressed as;

We are to determine the value of the function
![\frac{1}{4}  \lim_{x \to 0} [f(x)]^4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4)
This can also be expressed as
![\frac{1}{4}  \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4%5C%5C%20%3D%20%5Cfrac%7B1%7D%7B4%7D%284%29%5E4%20%5C%5C%3D1%2F4%5Ctimes%20256%5C%5C%3D64)
Hence the limit of the given function if  is 64
 is 64
Learn more on limit of a function here: brainly.com/question/23935467
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Answer:
y = 3
Step-by-step explanation:
(5y - 3)/4 + 6 = 3y
5y - 3 + 24 = 12y
7y = 21
y = 3
Check. 
(5*3 - 3)/4 + 6 = 3*3
(15 - 3)/4 + 6 = 9
12/4 + 6 = 9
3 + 6 = 9
9 = 9
 
        
                    
             
        
        
        
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62. 
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.
To find the missing distance in the right triangle. You have to use the Pythagorean Theorem.  I set it up and solve it below.
a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)
        
             
        
        
        
9514 1404 393
Answer:
   20.3
Step-by-step explanation:
The distance formula can be used to find the side lengths.
   d = √((x2 -x1)^2 +(y2 -y1)^2)
For the first two points, ...
   d = √((3 -(-2))^2 +(6 -3)^2) = √(5^2 +3^2) = √34 ≈ 5.83
For the next two points, ...
   d = √((2 -3)^2 +(-2-6)^2) = √(1 +64) = √65 ≈ 8.06
For the last and first points, ...
   d = √((-2-2)^2 +(3-(-2)^2) = √(16 +25) = √41 ≈ 6.40
Then the sum of the side lengths is ...
   5.83 +8.06 +6.40 = 20.29 ≈ 20.3
The perimeter of the triangle is about 20.3 units.