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faltersainse [42]
3 years ago
9

PLEASE HELP EZ MATH AND ILL GIVE BRAINLIEST

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:1.9

Step-by-step explanation:

Frank had 24.74 gallons of gasoline in his morning's vehicle. Now, there are left 1.9 gallons. How much was Frank using fuel? Frank had 24.74 gallons of gasoline this morning. Now, there are left 1.9 gallons. How much was Frank using fuel? Frank had 24.74 gallons of gasoline this morning. Now, there are left 1.9 gallons. How much was Frank using fuel? Frank had 24.74 gallons of gasoline this morning. Now, there are 1.9 gallons.

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A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
lesya692 [45]

Answer:

The probability that a call last between 4.2 and 4.9 minutes is 0.4599

Step-by-step explanation:

Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

W = \frac{X-\mu}{\sigma} = \frac{X-4.2}{0.4}

We will use \phi , the cummulative distribution function of W. The values of \phi are well known and the can be found in the attached file

P(4.2 < X < 4.9) = P(\frac{4.2-4.2}{0.4} < \frac{X-4.2}{0.4} < \frac{4.9-4.2}{0.4}) = P(0 < W < 1.75) = \\ \phi(1.75) - \phi(0) = 0.9599-0.5 = 0.4599

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599

Download pdf
7 0
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