Question

I'm really having trouble with this one. It says: Use your graphing calculator to find the value of f'(0) for f(x) = sin(x) + e^x.​

Answer 1

Step-by-step explanation:

f'(x) = d/dx [f(x)]

= d/dx (sinx + e^x) = cosx + e^x.

Therefore f'(0) = cos(0) + e^(0) = 2.