3 years ago

16ef³÷8e²f=24m²n³_=2mn2k³+k_=4k

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer:

Answer is below

Step-by-step explanation:

16ef³÷8e²f= $\frac{2f^{2}}{e}$

$\frac{24m^{2} n^{3} }{2mn} = 12m n^{2}$

$\frac{2k^{3} +k}{4k} =\frac{1}{2} k^{2} +\frac{1}{4}$

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16ef³÷8e²f=24m²n³_____=2mn2k³+k_____=4k​

16ef³÷8e²f=24m²n³_=2mn2k³+k_=4k