Question

16ef³÷8e²f=24m²n³_____=2mn2k³+k_____=4k​

Answer 1

Answer:

Answer is below

Step-by-step explanation:

16ef³÷8e²f=$\frac{2f^{2}}{e}$

$\frac{24m^{2} n^{3} }{2mn} = 12m n^{2}$

$\frac{2k^{3} +k}{4k} =\frac{1}{2} k^{2} +\frac{1}{4}$