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vodomira [7]
2 years ago
8

16ef³÷8e²f=24m²n³_____=2mn2k³+k_____=4k​

Mathematics
1 answer:
hjlf2 years ago
3 0

Answer:

Answer is below

Step-by-step explanation:

16ef³÷8e²f=\frac{2f^{2}}{e}

\frac{24m^{2} n^{3} }{2mn} = 12m n^{2}

\frac{2k^{3} +k}{4k} =\frac{1}{2} k^{2} +\frac{1}{4}

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