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maria [59]
3 years ago
14

5. Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0
–4j²<span> + 3j – 28 = 0
D = b</span>² - 4ac = 3² - 4*(-4)*(-28) = 9 - 448 = -439
D<0  ⇒  j ∈ ∅
<span>No solutions</span>
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