For Question 1:
angle CAB, angle ABC, angle BCA
Question 2: angle BCD
Question 11a)
We are given side BC equals to side CE and angle CBA equals to angle CED
We also know that angle ACB equals to angle ECD are equal (opposite angles properties)
We have enough information to deduce that triangle ABC and triangle CDE are equal by postulate Angle-Side-Angle (ASA)
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Question 11b)
We are given side AB equal to side ED, side BC equals to side EF, and side AC equals to side DF
We have enough information to deduce that triangle ABC and triangle DEF congruent by postulate Side-Side-Side (SSS)
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Question 11c)
We are given side AC equals to side DF, angle ABC equals to angle DEF, and angle BAC equals to angle EDF
We have enough information to deduce that triangle ABC congruent to triangle DEF by postulate Angle-Side-Angle (ASA)
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Question 11d)
We do not have enough information to tell whether this shape congruent or not
Answer:
Step-by-step explanation:
Given is the absolute value function.
<u>Observations:</u>
- It has a slope of ±√3 and the y- intercept of 2.
- There is no horizontal shift, so the the y-axis is the line of symmetry.
- The y-axis is also an angle bisector of the two lines.
- The foot P₁P₂ is parallel to the x-axis since it's perpendicular to the y- axis.
We need to find the coordinates of intersection of the line P₁P₂ with the y- axis (the point Y in the picture).
Consider the triangle AYP₂.
We know AP₂ = 5.
<u>The angle YAP₂ is:</u>
<u>The distance AY is:</u>
- AY = AP₂ cos 30° = 5*√3/2
<u>The distance from the x-axis to the point Y is:</u>
- 5√3/2 + 2, added the y- intercept of the graphed lines
<u>The coordinates of the point Y:</u>
215/54 i hope that helped you bye thanks
