Answer:
14.87% per hour
Step-by-step explanation:
Let's pretend we're starting with one bacteria.
Double of one is two
We're gonna have to use this formula: A = P(1 + x)ⁿ
A = Amount (which is 2)
P = Initial amount (which is 1)
x = percentage per time (hour)
n = amount of time (hours)
So our equation will look like this:
2 = 1(1 + x)⁵
First, we need to root both sides to isolate (1 + x)
![\sqrt[5]{2} = \sqrt[5]{(1+x)}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%7D%20%3D%20%5Csqrt%5B5%5D%7B%281%2Bx%29%7D)
![\sqrt[5]{2} = 1 +x](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%7D%20%3D%201%20%2Bx)
Then subtract both sides by 1
![\sqrt[5]{2}-1 = 1 +x - 1](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%7D-1%20%3D%201%20%2Bx%20-%201)
![x=\sqrt[5]{2}-1](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B5%5D%7B2%7D-1)
![\sqrt[5]{2} = 1.148698355](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%7D%20%3D%201.148698355)
1.148698355 - 1 = 0.148698355
x = 0.148698355
Answer:
Step-by-step explanation:
Since we have given that
Number of styrofoam balls bought by Bradley in May = 48
Number of toy figurines sold in May = 19
Number of styrofoam balls bought by Lupe in June = 44
Number of toy figurines sold in June = 21
So, we need to make a matrix that represents all of their May purchases and their June sales :
So, it is given by
May June
Purchases Sales
Bradley 48 19
Lupe 49 21
Thus, we can define a 2x2 matrix in which row 1 represents Bradley and row 2 represents Lupe. The columns then represent May and June. To distinguish between purchase and sale, we will show sale by a positive number and sale with negative; therefore the final matrix will be
![\left[\begin{array}{ccc}48-19\\44-21\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D48-19%5C%5C44-21%5Cend%7Barray%7D%5Cright%5D)
Answer:
an = a(n-1) +5
Step-by-step explanation: