Well the answer is -2y-4 but the different terms in this problem are 4 and 5y and 3y where 5y and 3y are like terms
First, find the length
L^2+W^2=D^2 )L for length, W for width, D for diagonal)
L^2=25^2-15^2=625-225=400
L=20
A=1/2 of L*W= (1/2)*20*15=150 square inches
Quadrilateras
A C
Parallel lines
A B
The answer is sixty!
4(5+10)
4(15)
60
D = 14
1/6d + 2/3 = 1/4d - 1/2
2d + 4*2 = 3d - 6
2d - 3d = -6-8
-d = -14
d = 14
