If 4=2^2
8=2^3
(2^)2x+10=(2^)6x
(2^)6x-(2^)2x=10
(2^)2x×7=10, where x has no real value
Answer:
x^3
Step-by-step explanation:
It stays the same.
Hope this helps.
Answer:
Nwm miałem to dawno powodzenia
Answer:
x = - 4 ± 2
Step-by-step explanation:
Given
f(x) = x² + 8x + 4
To find the zeros let f(x) = 0, that is
x² + 8x + 4 = 0 ( subtract 4 from both sides )
x² + 8x = - 4
To solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(4)x + 16 = - 4 + 16
(x + 4)² = 12 ( take the square root of both sides )
x + 4 = ±
= ± 2
( subtract 4 from both sides )
x = - 4 ± 2
Thus the zeros are
x = - 4 - 2
and x = - 4 + 2