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3 years ago

Is 100% considered a rational or whole number?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

8 0

The number 100 is a rational number. It is a whole number, or integer.

arsen [322]3 years ago

7 0

<u>Ight Imma head out because I have no idea what you're saying</u>

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Polygon ABCD is rotated 90° counterclockwise about the origin to create polygon A'B'C'D'. natch each set of coordinates to the v

Sati [7]

These questions are no problem, so long as you remember the rules for rotations. A point that is rotated 90 counterclockwise is simply x and y flipped, and negating the y.

For example, 2,9 becomes -9, 2.

So point A would be -1, 1, B would be -2, 1. So on and so forth.

5 0

3 years ago

A 14 foot is cut into two pieces so that one piece is 3 feet longer than twice the shorter piece

DochEvi [55]

To answer the question above, let x be the shorter one of the pieces. With the variable, we can express the longer piece as 2x + 3. Based on the given, the sum of the lengths of these pieces should sum up to 14 ft.

2x + 3 + x = 14 ft, x = 3 2/3 ft

Substituting this value for the longer piece, we get 10 1/3 ft. Thus, the lengths of the pieces are 3 2/3 ft and 10 1/3 ft.

3 0

3 years ago

Im having math trouble please help

Marysya12 [62]

well divide 4/5

Step-by-step explanation:

that Will your answer

5 0

3 years ago

Read 2 more answers

Determine cosine 23 degrees:

dexar [7]

$cos23^o\approx0,9205$

7 0

4 years ago

I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be

Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

$P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}$

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: $g'(-1)\,(1)$ since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: $g'(-1)= 7$ as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0

3 years ago